Overview

Quadratic functions produce parabola-shaped graphs and appear extensively in SAT Advanced Math, both as standalone function questions and in real-world modeling contexts. The SAT presents quadratic functions in three interchangeable forms, and the ability to read information directly from each form — and convert between forms efficiently — is a high-yield skill. The digital SAT’s Desmos calculator makes graphical verification fast and reliable.


Key Points

1. Three Forms of a Quadratic Function

FormEquationWhat It Reveals Directly
Standardf(x) = ax² + bx + cy-intercept (c), direction (sign of a)
Vertexf(x) = a(x - h)² + kVertex (h, k), axis of symmetry x = h
Factoredf(x) = a(x - p)(x - q)x-intercepts (roots) p and q

The value of a is shared across all three forms and determines:

  • a > 0 → parabola opens upward (minimum exists)
  • a < 0 → parabola opens downward (maximum exists)
  • |a| larger → narrower parabola; |a| smaller → wider parabola

2. Vertex and Axis of Symmetry

From standard form:

Axis of symmetry:  x = -b / (2a)
Vertex x-coordinate:  h = -b / (2a)
Vertex y-coordinate:  k = f(h) = substitute h back into f(x)

From vertex form:

f(x) = a(x - h)² + k
Vertex is directly (h, k)
Axis of symmetry is x = h

Note: In vertex form, the sign inside the parentheses is opposite to h. If the form is f(x) = a(x + 3)² + k, then h = -3 (not +3).


3. Converting Between Forms

Standard → Vertex (complete the square):

f(x) = x² + 6x + 5
     = (x² + 6x + 9) - 9 + 5
     = (x + 3)² - 4
Vertex: (-3, -4)

Factored → Standard (expand):

f(x) = 2(x - 1)(x - 4) = 2(x² - 5x + 4) = 2x² - 10x + 8

Standard → Factored (factor):

f(x) = x² - 5x + 6 = (x - 2)(x - 3)   →   roots: x = 2, 3

4. Key Graph Features

FeatureHow to Find
y-interceptSet x = 0; equals c in standard form
x-intercepts (roots)Set f(x) = 0; use factoring or quadratic formula
Vertexx = -b/2a; or read directly from vertex form
Axis of symmetryx = h (same as vertex x-coordinate)
Maximum/Minimum valuey-coordinate of vertex; min if a>0, max if a<0

5. Maximum and Minimum in Context

On the SAT, word problems about quadratic functions often ask for:

  • Maximum profit → find vertex y-coordinate when a < 0
  • Maximum height → find vertex y-coordinate of a projectile equation
  • When max/min occurs → find vertex x-coordinate

Example pattern:

“The height h (in feet) of a ball is given by h(t) = -16t² + 64t + 5. What is the maximum height?“

t_vertex = -64 / (2·(-16)) = -64 / -32 = 2 seconds
h(2) = -16(4) + 64(2) + 5 = -64 + 128 + 5 = 69 feet

6. Digital SAT: Desmos Strategy

  • Graph the quadratic → identify vertex, x-intercepts, direction directly
  • Regression method (3 points given): open Desmos table, enter (x, y) pairs, type y₁ ~ ax₁² + bx₁ + c to fit
  • Solve for intersections: graph quadratic and any other equation, click intersection points

Pitfalls and Common Mistakes

Pitfall 1: Sign error reading h from vertex form f(x) = a(x + 3)² + k → students read h = +3, but correct h = -3. Fix: Rewrite as f(x) = a(x - (-3))² + k. The vertex is (-3, k), not (3, k).

Pitfall 2: Confusing axis of symmetry with a solution The axis of symmetry x = -b/(2a) is NOT a solution to the equation — it is the x-coordinate of the vertex. Fix: Clearly distinguish between “vertex x-coordinate” and “roots of the equation.”

Pitfall 3: Forgetting the negative sign for downward parabolas If a < 0, the vertex is a maximum, not a minimum. Fix: Always note the sign of a first before labeling vertex as max or min.

Pitfall 4: Wrong y-intercept In vertex form f(x) = a(x-h)² + k, students write the y-intercept as k. Fix: Substitute x = 0: y-intercept = a(0-h)² + k = ah² + k.

Pitfall 5: Expanding vertex form incorrectly

WRONG: a(x - h)² = ax² - ah²
RIGHT: a(x - h)² = a(x² - 2hx + h²) = ax² - 2ahx + ah²

Fix: Always expand (x - h)² = x² - 2hx + h² fully before multiplying by a.



Quick Reference Card

ConceptFormula / Rule
Standard formf(x) = ax² + bx + c
Vertex formf(x) = a(x - h)² + k
Factored formf(x) = a(x - p)(x - q)
Axis of symmetryx = -b/(2a)
Vertex from standard(-b/2a, f(-b/2a))
Opens upa > 0 (minimum at vertex)
Opens downa < 0 (maximum at vertex)
y-intercept(0, c) in standard form
x-interceptsRoots of ax²+bx+c=0
Vertex h from vertex formh is opposite sign: f(x-h) means h is positive